3x^2-6.75=0

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Solution for 3x^2-6.75=0 equation: 



3x^2-6.75=0

a = 3; b = 0; c = -6.75;
Δ = b2-4ac
Δ = 02-4·3·(-6.75)
Δ = 81
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{81}=9$


$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-9}{2*3}=\frac{-9}{6}
=-1+1/2
$


$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+9}{2*3}=\frac{9}{6}
=1+1/2
$

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